Finding the Equations of a Circle with Given Conditions: A Step-by-Step Guide
Finding the Equations of a Circle with Given Conditions: A Step-by-Step Guide
In this article, we will explore how to find the equations of a circle given specific conditions. We will use the example of a circle with a radius of 10 units, which passes through a particular point and has the x-axis as a tangent. We will break down the problem into several steps and show you how to apply the concepts of circle equations and tangents to arrive at the solution.
Problem Statement
A circle has a radius of 10 units and passes through the point (5, -16). The x-axis is a tangent to this circle. Determine the possible equations of the circle under these conditions.
Step 1: Determine the Center of the Circle
Since the x-axis is a tangent to the circle, the distance from the center of the circle to the x-axis must equal the radius. If the center of the circle is at (h, k), then:
(k 10)
This gives us two possible values for k: 10 and -10.
Step 2: Use the Point that the Circle Passes Through
The equation of a circle with center (h, k) and radius r is given by:
( (x - h)^2 (y - k)^2 r^2 )
Substituting (r 10), we have:
( (x - h)^2 (y - k)^2 100 )
Case 1: k 10
Substituting (k 10):
( (5 - h)^2 (-16 - 10)^2 100 )
Calculating the second term:
( (5 - h)^2 (-26)^2 100 )
This simplifies to:
( (5 - h)^2 676 100 )
Rearranging gives:
( (5 - h)^2 100 - 676 )
( (5 - h)^2 -576 )
Since a square cannot equal a negative number, there are no valid circles for this case.
Case 2: k -10
Now substituting (k -10):
( (5 - h)^2 (-16 - (-10))^2 100 )
Calculating the second term:
( (5 - h)^2 (-6)^2 100 )
This simplifies to:
( (5 - h)^2 36 100 )
Rearranging gives:
( (5 - h)^2 100 - 36 )
( (5 - h)^2 64 )
Taking the square root:
( 5 - h 8 ) or ( 5 - h -8 )
This gives us two possible values for h:
( h -3 ) or ( h 13 )
Step 3: Write the Equations of the Circles
Now we can formulate the equations of the circles based on the centers we found:
For the center ((-3, -10)):
( (x 3)^2 (y 10)^2 100 )
For the center ((13, -10)):
( (x - 13)^2 (y 10)^2 100 )
Final Answer
The possible equations of the circles are:
( (x 3)^2 (y 10)^2 100 )
( (x - 13)^2 (y 10)^2 100 )
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